2x^2-12x+41=0

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Solution for 2x^2-12x+41=0 equation:


Simplifying
2x2 + -12x + 41 = 0

Reorder the terms:
41 + -12x + 2x2 = 0

Solving
41 + -12x + 2x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
20.5 + -6x + x2 = 0

Move the constant term to the right:

Add '-20.5' to each side of the equation.
20.5 + -6x + -20.5 + x2 = 0 + -20.5

Reorder the terms:
20.5 + -20.5 + -6x + x2 = 0 + -20.5

Combine like terms: 20.5 + -20.5 = 0.0
0.0 + -6x + x2 = 0 + -20.5
-6x + x2 = 0 + -20.5

Combine like terms: 0 + -20.5 = -20.5
-6x + x2 = -20.5

The x term is -6x.  Take half its coefficient (-3).
Square it (9) and add it to both sides.

Add '9' to each side of the equation.
-6x + 9 + x2 = -20.5 + 9

Reorder the terms:
9 + -6x + x2 = -20.5 + 9

Combine like terms: -20.5 + 9 = -11.5
9 + -6x + x2 = -11.5

Factor a perfect square on the left side:
(x + -3)(x + -3) = -11.5

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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